
Though one may not know the technical
definition of the Conservation of Angular Momentum, most people are aware of
the process. For instance one may see a yo-yo being swung in a
circle. As the string wraps around the plastic piece every revolution,
the string shortens and the yo-yo will circle more quickly. Close
observation of a tornado will reveal that the narrower bottom of the cloud
rotates at a greater speed than the portion closest to the storm cloud.
What can explain this phenomenon that affects so many aspects of life?
All of the above exist due to the Conservation of Angular
Momentum. Any object executing motion around a point possesses angular
momentum. The Conservation of Angular Momentum states that the total
angular momentum at one instant in time has to equal the total angular momentum
at another instant in time in a system. It is illustrated by its
equation:
Ðp = mvr
m = mass of object/mass of smaller object (if two objects are used)
v = velocity of the object/velocity of smaller object (if two objects
are used)
r = radius/separation of the two objects
The letter "L" is often used to replace Ðp as the symbol for angular momentum.
The total angular momentum (Ðp)
is to remain the same, even though the values of m, v, and r
are subject to change. Therefore, if the mass of the object would
increase (decrease), the velocity and/or the radius must decrease
(increase). If the radius would increase (decrease), the velocity and/or
the mass would have to decrease (increase). Since it is most likely in a
situation that the object, and therefore the mass, would not change, the
velocity would have to be the factor to decrease (increase). And if the
velocity would increase (decrease), the mass and/or the radius would have to
decrease (increase). In this situation, it is also likely that the
object/mass would not be changed, and only the radius would decrease
(increase).
How does this relate to the examples given at the beginning
of the paper and why does the yo-yo spin faster as the string is shortened?
In this problem,
m = mass of the yo-yo
v = velocity at which the yo-yo is spinning
r = the length of the string from the hand of the person spinning the
yo-yo and the plastic piece
As the string is looped around the plastic piece of the
yo-yo it shortens, decreasing the value of r. Since the mass of
the yo-yo would not change, velocity would increase in this example.
The tornado works almost the same way as the yo-yo except in
this problem,
m = mass of the tornado
v = velocity at which the tornado rotates
r1 = the radius of the top of the tornado
r2 = the radius of the bottom of the tornado
It was stated that the top of the tornado spins more slowly
than the bottom of the tornado. This is because the radius of the top is
greater than that of the bottom (if you think of a typical tornado, you will
recall that it tapers as it gets closer to the ground). The angular
momentum must be conserved throughout the tornado. In the equation Ðp = mvr1, the
radius is larger than that of the equation Ðp
= mvr2. (Though the mass of the tornado may change as
it picks up more debris or changes its intensity, this does not factor into
this equation as it is examining the tornado at one fixed moment in
time.) Therefore, it is up to the velocity to change in response to the
difference in the radius. In equation 1, the radius is greater than that
of equation two: the velocity is less in equation 1 than it is in
equation 2.
Since our group's Pre-Calc exhibit was chiefly concerned
with the conservation of angular momentum of a tornado, I will assign actual
values to that equation to further illustrate how this scientific principle
works. (The following values are averages except for the mass.)
m = 1818kg
v1 = 94 mph
v2 = ?
r1 = 150 ft
r2 = 450 ft
Equation 1: Ðp = 1818 (94)
(150) = 25633800
Therefore,
Equation 2: 25633800 = 181 (?) (450)
? = v2 = 315 mph
This proves that the velocity at the
bottom of the tornado must be greater than the velocity at the top because the radius
at the bottom is less than that of the top.
Also so it is shown that the Conservation of Angular
Momentum does exist, proven by math and real-life examples. The angular
momentum of a system must be conserved throughout that system.
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